[Arduino]步進馬達實驗

好久沒來寫一下心得了

今天難得比較早下班，火速看一下別人的文章，

並且操作這個作業

以下為新北中山國中創客社群的文章來源為此

寫得很棒!!

28BYJ-48 步進馬達

1.外觀與尺寸 28BYJ-48 步進馬達有兩種規格 5V 與 12V ，尺寸大小都相同，但扭矩12V比5V稍大 通常可以由如下兩種驅動器ULN2003驅動(驅動器也同時支援5V與12V)          尺寸與規格表(尺寸可供3D列印設計時採用) 關於更詳細的測試請參閱   5V與12V的比較 3.內部齒輪比 (1) Adafruit gear train (2)RioRand gear train (3)一般版        #1  teeth: 9     #2 In:32 Out:11     #3 In:22 Out:9       #4 In:27 Out:8              #5 In:24  減速比 64:1       (輸入圈數：輸出圈數)     由上可知，若馬達步進角 5.625度 再乘以減速比得到輸出的解析度： 每步旋轉 5.625 x 1/64 = 0.087890625 度 若要轉一圈，需要  360/0.087890625 = 4096步 4.線路布置 28BYJ-48 步進馬達屬於四相五線步進馬達， 四相代表四組線圈 五線代表接出五條線 5.驅動法方為三種，每一種各有其優點與缺點，詳述如下 (1)一相激磁(優點：省電 缺點：轉矩小、轉速慢) 一相激磁驅動法，一圈需要2048步 int t= 10; void setup() { pinMode(8,OUTPUT); pinMode(9,OUTPUT); pinMode(10,OUTPUT); pinMode(11,OUTPUT); } void loop() { digitalWrite(8,1); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,1); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,1); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,1); delay(t); } 這是我的作業阿~~~很弱 (2)二相激磁 (優點：轉矩大 缺點：轉速慢、耗電) 二相激磁驅動法，一圈需要2048步 int t= 5; void setup() { pinMode(8,OUTPUT); pinMode(9,OUTPUT); pinMode(10,OUTPUT); pinMode(11,OUTPUT); } void loop() { digitalWrite(8,1); digitalWrite(9,1); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,1); digitalWrite(10,1); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,1); digitalWrite(11,1); delay(t); digitalWrite(8,1); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,1); delay(t); } 依然是弱弱的作業，我的t設定為10，轉速看不出來差別 或者是直接使用內建的函式庫 #include <Stepper.h> const int stepsPerRevolution = 2048; // change this to fit the number of steps per revolution // for your motor // initialize the stepper library on pins 8 through 11: Stepper myStepper(stepsPerRevolution, 4, 6, 7, 5); /* pin腳接法 IN1=4 IN2=6 IN3=7 IN4=5 */ void setup() { // set the speed at 60 rpm: myStepper.setSpeed(5); // initialize the serial port: Serial.begin(9600); } void loop() { // step one revolution in one direction: Serial.println("clockwise"); myStepper.step(stepsPerRevolution); delay(500); // step one revolution in the other direction: Serial.println("counterclockwise"); myStepper.step(-stepsPerRevolution); delay(500); } (3)一二相激磁(優點：精度提升2倍，可高轉速) 一二相激磁驅動法，一圈需要4096步 int t= 1; void setup() { pinMode(8,OUTPUT); pinMode(9,OUTPUT); pinMode(10,OUTPUT); pinMode(11,OUTPUT); } void loop() { digitalWrite(8,1); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,1); digitalWrite(9,1); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,1); digitalWrite(10,0); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,1); digitalWrite(10,1); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,1); digitalWrite(11,0); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,1); digitalWrite(11,1); delay(t); digitalWrite(8,0); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,1); delay(t); digitalWrite(8,1); digitalWrite(9,0); digitalWrite(10,0); digitalWrite(11,1); delay(t); } 弱弱作業來也 或者是 int t= 1000; boolean a[]={1,1,0,0,0,0,0,1}; boolean b[]={0,1,1,1,0,0,0,0}; boolean c[]={0,0,0,1,1,1,0,0}; boolean d[]={0,0,0,0,0,1,1,1}; void setup() { Serial.begin(115200); pinMode(8,OUTPUT); pinMode(9,OUTPUT); pinMode(10,OUTPUT); pinMode(11,OUTPUT); } void loop() { for(int i=0; i<8 ; i++){ digitalWrite(8,a[i]); digitalWrite(9,b[i]); digitalWrite(10,c[i]); digitalWrite(11,d[i]); delayMicroseconds(t); Serial.println(i); } }